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3 years ago

Calculate the area of the rectangle whose length:breath=3:2, perimeter =40cm

Mathematics

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

let 3:2 be 3x& 2x

perimeter =40

2(l+b)=40

2(3x+2x)=40

5x=40/2

x=20/5=4cm

length=3x=3×x=3×4=12cm

breadth =2x=2×4=8cm

area of rectangle =l×b=12×8=96cm²

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Laguna del carbon, a salt lake located in. Argentina, lies 344 feet below sea level. El alto, Bolivia, is located approximately

adelina 88 [10]

Answer:

The difference in elevation between Laguna del Carbon and El Alto is 12,656 feet.

Step-by-step explanation:

Given that Laguna del carbon, a salt lake located in Argentina, lies 344 feet below sea level, while El Alto, Bolivia, is located approximately 13,000 feet above sea level, to determine what is the difference in elevation between Laguna del Carbon and El Alto, the following calculation must be performed:

13,000 - 344 = X

12.656 = X

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3 years ago

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Diano4ka-milaya [45]

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3 years ago

Number 1d please help me analytical geometry

lesantik [10]

For a) is just the distance formula

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
% (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}$
-----------------------------------------------------------------------------------------
for b) is also the distance formula, just different coordinates and distance

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
% (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}$
--------------------------------------------------------------------------
for c) well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}$

now.. whatever that is, is = BC, so the distance for BC is

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
% (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
% distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}$

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d) we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
% (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\
$

$\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}$

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"

7 0

4 years ago

A box has a length of 15 centimeters, a width of 22 centimeters, and a height of 9 centimeters. What is the surface area of the

Alex777 [14]

Answer: 1,326

Step-by-step explanation:

I just had this question and this was the right answer! Glad I could help! May I have brainliest?

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3 years ago

1. If one side of the square is 12in, what is the perimeter and area of the parallelogram?

gayaneshka [121]

Answer:

Not sure for 1. Area might be 144. Perimeter might be 50. I got perimeter by finding slant height of the parallelogram and then substituting it to the perimeter formula (P=2(a+b) where a is a side and b is a base). I found area by just multiplying 12*12 since to find area of parallelogram, it is base x height.

2. 45, 135, 135

Step-by-step explanation:

2. We know that an isosceles trapezoid has congruent base angles and congruent upper angles, so if one base angle measures 45 degrees, the other base angle will also be 45 degrees.

For the upper angles, we know that diagonal angles are supplementary, so 180- base angle 1 (45 degrees)= upper angle 1

180-45=upper angle 1

upper angle 1 = 135 degrees

Mentioned above, upper angles are congruent, so upper angles 1 and 2 will be 135 degrees.

Check: The sum of angles in a quadrilateral is equal to 360 degrees. We can use this to check if our answer is correct.

135+135=270 degrees (sum of upper angles)

45+45= 90 degrees (sum of base angles)

270+90=360

So the angle measures of the other three angles are 135, 135, and 45.

Hope this helps!

7 0

3 years ago

Calculate the area of the rectangle whose length:breath=3:2, perimeter =40cm​

Calculate the area of the rectangle whose length:breath=3:2, perimeter =40cm