Answer:
Monthly payment = $268.32
Over the 10 years interest
= $32198.4
Step-by-step explanation:
According to the question
James will be paying his interest on a monthly basis.
So let's calculate how much the interest of a month it's going to be become with
P = 64397
R = 5
T =1/12
I = (64397*5*(1/12))/100
I = 321985*(1/12)/100
I = 26832.08333/100
I = 268.32
I = $268.32
So he will be paying$ 268.32 every month for 10 years
But in 10 years we have 10*12= 120 months
So total interest = 120*268.32
= $32198.4
6000 x 10% x 5
=600x5
=3000
Did you ever get the answer?
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be , where is the stopping distance measured in metres and is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of .
2) Add the function .
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
For determining the period of a function, you pick two recognizable tops of the graph and calculate the time difference between them. In this situation the period is 5-1=4, by picking the first two tops