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harkovskaia [24]
2 years ago
7

Which of the following best describes the graph below?

Mathematics
2 answers:
Fofino [41]2 years ago
8 0
The screen is dark so i cant see it
ValentinkaMS [17]2 years ago
7 0
Your picture is black ?
You might be interested in
I don't understand how to do this, can someone please help me?
denis23 [38]

Answer:

x=1

Step-by-step explanation:

First find a common denominator between 7 and 4 which is 28, Multiply both equations by 28 eliminating the denominators so now you have theses two equations: 4(2x + 12) = 7(3x + 5) distribute these equations to get:

8x + 48 = 21x +35 now you want to get the x's on one side so 8-21 = -13 which as an equation so far would be -13x + 48 = 35 now do 35-48 = -13 so you can have 13x alone on one side. Your final equation now before you solve is

-13x = -13 the divide -13 by -13 to get 1.

Hope this helps you understand it better

4 0
3 years ago
Find the distance and midpoint for the points (5,5) and (1,2).
nikklg [1K]

Answer: wtfffff

Step-by-step explanation:

4 0
3 years ago
Find the x- and y-intercepts for the linear equation –3x + 4y = 24.
Sav [38]

Answer:

x- intercept = - 8, y- intercept = 6

Step-by-step explanation:

To find the x- intercept let y = 0 and solve for x

- 3x + 4(0) = 24

- 3x = 24 ( divide both sides by - 3 )

x = - 8 ← x- intercept

To find the y- intercept let x = 0 and solve for y

- 3(0) + 4y = 24

4y = 24 ( divide both sides by 4 )

y = 6 ← y- intercept

3 0
2 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
Solve the system of equations by substitution. Show your work in the sketch and write your answer as an ordered pair.
Ede4ka [16]

Let's solve your system by substitution.

−3x+y=−2;y=4x

Rewrite equations:

y=4x;−3x+y=−2

Step: Solvey=4xfor y:

y=4x

Step: Substitute4xforyin−3x+y=−2:

−3x+y=−2

−3x+4x=−2

x=−2(Simplify both sides of the equation)

Step: Substitute−2forxiny=4x:

y=4x

y=(4)(−2)

y=−8(Simplify both sides of the equation)

Answer:

x=−2 and y=−8

3 0
3 years ago
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