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3 years ago

What is the midpoint of the line segment with endpoints (1,-6) and (-3,4)?

Mathematics

1 answer:

kirill115 [55]3 years ago

8 0

Answer:

(-1,-1)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

(1+-3)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

(-6+4)/2 = -2/2 = -1

(-1,-1)

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A circular go-kart track has a diameter of 75 meters. Approximately how long is the track? A225 meters B100 meters C750 meters D

worty [1.4K]

Answer:

<h2> 235 meters</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, a circular shape.

the problem also requires that we find the perimeter of the circular track

the expression for the perimeter of a circle is given as

$C= 2\pi r$

Given

diameter of the circular track = 75 meters

radius of circular track = d/2 = 75/2= 37.5 meters

Substituting our data into the expression for perimeter we have

$C= 2*3.142 *37.5\\\\C= 235.65$

<em>Approximately the length is 235 meters.</em>

8 0

3 years ago

inez read 48 pages of her book in 30 minutes. how many pages can she read in 45 minutes. show/type work

Paladinen [302]

48 pages -> 30 minutes
(1.5)48 pages -> 30 (1.5) minutes
72 pages -> 45 minutes
She can read 72 pages in 45 minutes.

*Hope that helps! :)

5 0

3 years ago

QUICKEST AND MOST CORRECT ANSWER GETS BRAINLIEST 0LUS ILL FOLLOW U

RideAnS [48]

Answer:

Step-by-step explanation:

-2x-1 =y

-2x 2= -4-1

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3 years ago

Write the monomial in standard form. name it's coefficient and identify its degree.

Hunter-Best [27]

Answer:

$Standard\ Form = {3n^2} m^{-2}$

Step-by-step explanation:

Given

$\frac{2}{3m^2n} * 4.5n^3$

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

$\frac{2}{3m^2n} * 4.5n^3$

$Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}$

Split the numerator and the denominator

$Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}$

Multiply Like terms

$Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}$

Divide 9 by 3 to give 3

$Standard\ Form = \frac{3 * n^3}{m^2 * n}$

Divide n³ by n to n²

$Standard\ Form = \frac{3 * n^2}{m^2 }$

Split fraction

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$

From laws of indices;

$\frac{1}{a^n} = a^{-n}$

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$ becomes

$Standard\ Form = {3 * n^2} * m^{-2}$

Multiply all together

$Standard\ Form = {3n^2} m^{-2}$

5 0

3 years ago

Ab + c = d solve for a

ch4aika [34]

Answer:

a=d-c/b

Subtract c from both sides

a=d-c/b

divide both sides by b

7 0

3 years ago

Read 2 more answers