You would use the equation
F+V=E+2
Answer: ![x = \pm2\sqrt{7}\\\\](https://tex.z-dn.net/?f=x%20%3D%20%5Cpm2%5Csqrt%7B7%7D%5C%5C%5C%5C)
Work Shown:
![x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}\\\\](https://tex.z-dn.net/?f=x%5E2%20%3D%2028%5C%5C%5C%5Cx%20%3D%20%5Cpm%5Csqrt%7B28%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm%5Csqrt%7B4%2A7%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm%5Csqrt%7B4%7D%2A%5Csqrt%7B7%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm2%5Csqrt%7B7%7D%5C%5C%5C%5C)
This can be rewritten into ![x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}](https://tex.z-dn.net/?f=x%20%3D%202%5Csqrt%7B7%7D%20%5C%20%5Ctext%7B%20or%20%7D%20%5C%20x%20%3D%20-2%5Csqrt%7B7%7D)
Answer:
There are less than 5 1/2 cups of sugar.
Step-by-step explanation:
E D G E N U I T Y
Have a good day! (◕ヮ◕ヽ)
Answer:
(a) Test statistic is -2.85 and p-value is 0.0022
(b) Reject the null hypothesis. The population mean of dissolved oxygen content is not equal to 10 mg/L
Step-by-step explanation:
H0: mu equals 10
Ha: mu not equals 10
The test is a two-tailed test because the alternate hypothesis is expressed using not equal to
(a) Test statistic (z) = (sample mean - population mean) ÷ (sd/√n) = (9.14 - 10) ÷ (2/√44) = -0.86 ÷ 0.302 = -2.85
Cumulative area of the test statistic = 0.9978
p-value = 2(1 - 0.9978) = 2(0.0022) = 0.0044
(b) The critical value using 0.02 significance level is 2.422. For a two-tailed test, the region of no rejection of the test statistic lies between -2.422 and 2.422.
Conclusion:
Reject the null hypothesis because the test statistic -2.85 falls outside the region bounded by the critical values -2.422 and 2.422.
The population mean of dissolved oxygen content is not equal to 10 mg/L
Answer:
You need 10 of those numbers to be whole numbers, decimals, or fractions (THESE ARE RATIONAL)
You need the other 10 of those numbers to radicals, or numbers similar to pi (THESE ARE IRRATIONAL)
Step-by-step explanation: