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3 years ago

8

Bob invests $18818 in an account that pays 7.24% interest per year for 5 years. Ilo much simple interest will he cam? Round your

answer to the nearest penny if necessary.

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

25,968.84 interest in 5 years

Step-by-step explanation:

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Paolo Portraits charges $15 per photo with no sitting fee. The graph shows the fees for clear image studio.Compare the functions

liubo4ka [24]

Answer:

The rate of change of Paolo Portraits is $15 per photo and the rate of change of clear image studio is $12 per photo. Paolo Portraits charges are higher than the clear image studio.

Step-by-step explanation:

The rate of change represent the change in one variable with respect to another variable. It also known as slope.

It is given that Paolo Portraits charges $15 per photo with no sitting fee. It means the rate of change of Paolo Portraits is $15 per photo.

The function for Paolo Portraits charges is defined as

$f(x)=15x$

From the given graph it is noticed that the line is passing through the points (0,0) and (1,12).

The slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{12-0}{1-0}=\frac{12}{1}=12$

The function for clear image studio is

$g(x)=12x$

It means the rate of change of clear image studio is $12 per photo.

The rate of change of Paolo Portraits is more than rate of change of clear image studio.

Therefore Paolo Portraits charges are higher than the clear image studio.

3 0

3 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0

2 years ago

Fre-e points <br><br><br><br> 915 9482 0043 Gm1fgZ<br> join

Minchanka [31]

Answer:

Thanks, but join what?

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

How do you determine which variable to substitute in for?

stira [4]

Answer:

Substituting for a Variable

If you know the value that the variable is equal to, you can substitute that value in for the variable in the expression! Let's look at an example. Since we know that x=5, we can directly substitute or replace the x in the expression x+3 with a 5 to solve for y!

Step-by-step explanation:

I hope this kinda helps

7 0

3 years ago

A town has a population of 32,000 in the year 2002; 38,400 in the year 2003; 46,080 in the year 2004; and 55,296 in the year 200

NeTakaya

The point is to find the growth rate. The compound formula is:

P=A(1+ growth rate)ⁿ, where A is the initial Value & P the new value after n years:
P₂₀₀₃ =P₂₀₀₂ (1+ growth rate)¹ (the period "n" from 2002 to 2003 being 1 year)

38400 = 32000(1+growth rate)¹
38400 / 32000 - 1= growth rate & growth rate = 1/5 = 0.2
You will balso find the same growth rate for:
P₂₀₀₄ = P₂₀₀₃(1+ growth rate)¹
P₂₀₀₅ = P₂₀₀₄((1+ growth rate)¹
between 2015 & 2002 THERE ARE 14 YEARS:

P₂₀₁₅ = P₂₀₀₂(1+0.2)¹⁴ & P₂₀₁₅ = 32000(1+02)¹⁴ = 410,854

8 0

3 years ago