Answer:
Step-by-step explanation:
Given the circumference of Circle K = π
circumference of Circle L = 4π
Ratio of their circumferences = Ck/Cl
Ratio of their circumferences = π/4π
Ratio of their circumferences = 1/4 = 1:4
For their radii
C = 2πr
for circle k with circumference π
π = 2πrk
1 = 2rk
rk = 1/2
for circle l with circumference 4π
4π = 2πr
4 = 2r
r = 4/2
rl = 2
ratio
rk/rl = 1/2/2
rk/rl = 1/4 = 1:4
for the areas
Area of a circle = πr²
for circle k
Ak = π(1/2)²
Ak = π(1/4)
Ak = π/4
for circle l
Al = π(2)²
Al = 4π
Ratio of their areas
Ak/Al = π/4/(4π)
Ak/Al = π/16π
Ak/Al = 1/16 = 1:16
I'm pretty sure the answer is checking account A. Hope this helps
Answer:
See explanation
Step-by-step explanation:
<u> ASA Postulate (Angle-Side-Angle):</u>
If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
Consider triangles XYB and ZYA. In these triangles
- ∠X≅∠Z (given)
- XY≅ZY (given)
- ∠Y is common angle
By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so
BX≅AZ
Answer:
11y-2x= -90
Step-by-step explanation:
for the point (1,-8)
x=1 and y= -8
for the equation,
2x -4y= -11
x= -1/m
m= -1/x
x = -1/ (-11/2 )
m= 2/11
so for the equation,
y-y1= m(x- x1)
y- -8=2/11(x-1)
11(y+8)= 2(x-1)
11y +88= 2x-2
11y-2x= -90