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Nadusha1986 [10]
3 years ago
6

A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

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I need help with this practice I am having a tough time solving it properly
Monica [59]

Given:

There are given that the parent functions as a cosine function:

Where,

The amplitude of the function is 9.

The vertical shift is 11 units down.

Explanation:

To find the cosine function, we need to see the standard form of the cosine function:

f(x)=acos(bx+c)+d

Where,

a is the amplitude of the function,

Now,

According to the question:

The amplitude of the function is 9, which means:

f(x)=9cos(bx+c)+d

The vertical shift is 11 units down, which means:

f(x)=9cos(bx+c)-11

For period:

\begin{gathered} f(x)=-9cos(\frac{12\pi}{7}x+0)-11 \\ f(x)=-9cos(\frac{12\pi}{7}x)-11 \end{gathered}

Final answer:

Hence, the cosine function is shown below;

f(x)=-9cos(\frac{12\pi}{7}x)-11

4 0
1 year ago
Which is the last operation performed when evaluating (8-2x)^2+4 for x=3
Salsk061 [2.6K]
Addition will be the last operation
6 0
3 years ago
Read 2 more answers
What is the domain of y = cos θ?
Tpy6a [65]

Domain are all the possible x values of a function. When you look at a cosine graph you can see that it goes on into infinity in the x or horizontal direction. This means that all x values are included in cosine. Because of this the domain is:

all real numbers

or

(-∞,∞)

^^^ It can be written both ways

Hope this helped! Let me know if there is anything else I can do!

7 0
2 years ago
The vector 〈4,1〉 describes the translation of A(-1, w) to A'(2x+1,\ 4) and B(8y-1,1) onto B'(3,3z) . Find the values of w, x, y,
expeople1 [14]

The values of the variables associated ot translation operations are (w, x, y, z) = (3, 1, 0, 2 / 3).

<h3>How to determine the values of the variables associated to translation operations</h3>

Herein we find two translation cases of points set on Cartesian plane. Translations are rigid operations of the form:

P'(x, y) = P(x, y) + T(x, y)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • T(x, y) - Translation vector

Now we proceed to determine the values of the variables w, x, y, z behind each translation operation, substitute on each component and solve the resulting formula:

T(x, y) = A'(x, y) - A(x, y)

(2 · x + 1, 4) - (- 1, w) = (4, 1)

(2 · x + 2, 4 - w) = (4, 1)

(x, w) = (1, 3)

T(x, y) = B'(x, y) - B(x, y)

(3, 3 · z) - (8 · y - 1, 1) = (4, 1)

(4 - 8 · y, 3 · z - 1) = (4, 1)

(y, z) = (0, 2 / 3)

To learn more on translations: brainly.com/question/12463306

#SPJ1

6 0
1 year ago
4: Please help. What is the equation for ⨀C?
TEA [102]
It’s the second option
7 0
3 years ago
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