Prime factorisation of 49, 56,42 plz answer
2 answers:
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Answer:
Step-by-step explanation:
Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.
Therefore, we can set up the following equation to find the new balance after 2 years:
A) 0.9803; 0.4803
B) 32
We calculate the z-score for this problem by using the formula:
Using our formula, we have:
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.
To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.
To find B, we first find the z-score for this. Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33. We then set up our equation as
Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n
Divide both sides by 0.35:
1.9805/0.35 = √n
Square both sides:
(1.9805/0.35)² = n
32 ≈ n
B) 32
We calculate the z-score for this problem by using the formula:
Using our formula, we have:
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.
To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.
To find B, we first find the z-score for this. Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33. We then set up our equation as
Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n
Divide both sides by 0.35:
1.9805/0.35 = √n
Square both sides:
(1.9805/0.35)² = n
32 ≈ n