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3 years ago

HELPPPPP ME ASAP PLISSSSS

Chemistry

1 answer:

Airida [17]3 years ago

4 0

Answer:

25 cm3 of 0.15 mol dm-3 hydrogen peroxide

Explanation:

Not 100% with this one was a bit tricky.

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zimovet [89]

Answer:

B. False

Explanation:

step by step explanation

6 0

3 years ago

Read 2 more answers

Does rimmed steel contain nickel?

madam [21]

Answer: -

Rimmed steel does not contain nickel.

Explanation: -

Rimmed steel is a deoxidised low carbon steel. Deoxidation leads to formation of rims in the iron.

Carbon, sulfur and phosphorus is present in rimmed steel. The concentrations of these vary from the outer rim to the inner rim. It is not as tough as other steel.

Hence it is primarily used for products where a lot of bending is required. Thus Rimmed steel does not contain nickel.

7 0

3 years ago

Ivanshal [37]

Answer:

$HCl conc=2.2M$

Explanation:

From the question we are told that:

Mass of zinc $Mass_{z_n}=2.5g$

Initial conc of HCl $HConc_1=6.0M$

Initial volume of HCl $Hvol_1=20.0mL$

Molar mass of zinc $M_{Z_n}=65.38g/mol$

Generally the equation for reaction is mathematically given by

$2HCL+Zn\implies ZnCl_2 +H_2$

Generally the equation for moles of zinc $m_{z_n}$ is mathematically given by

$m_{z_n}=\frac{Mass_{Z_n}}{M_{Z_n}}$

$m_{z_n}=\frac{2.5g}{M_{65.38}}$

$m_{z_n}=0.038molZn$

Generally the equation for moles of $m_{HCl}$ is mathematically given by

$m_{HCl}=HConc_1*Hvol_1$

$m_{HCl}=6.0M*20.0mL$

$m_{HCl}=6.0M*20.0*10^{-3}L$

$m_{HCl}=0.12\ mol\ HCl$

Generally the reacted moles of HCl $HCl_[reacted]$ is mathematically given by

Since

Zn:HCl =1:2

Therefore

$HCl_[reacted]=0.038*\frac{2}{1}$

$HCl_[reacted]=0.076mol \ HCl$

Generally the moles of HCl after Zn oxidization X is mathematically given by

$x=0.12-0.076$

$x=0.044 mol HCl$

Generally the conc of hydrochloride acid X is mathematically given by

$X=\frac{0.044}{0.020}$

$X=2.2 M Hcl$

Therefore Conc of HCl

$HCl conc=2.2M$

5 0

3 years ago

A 25.00 mL sample of of a sulfurous acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is t

Kryger [21]

Answer:

0.0445 M is the initial concentration of sulfurous acid.

Explanation:

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_3$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=25.00mL\\n_2=1\\M_2=0.13 M\\V_2=17.12 mL$

Putting values in above equation, we get:

$2\times M_1\times 25.00 mL=1\times 0.13 M\times 17.12 mL$

$x=\frac{1\times 0.13 M\times 17.12 mL}{2\times 25.00}=0.0445 M$

0.0445 M is the initial concentration of sulfurous acid.

8 0

3 years ago

Boyle's Law expresses the pressure-volume

Colt1911 [192]

Answer:

$\large \boxed{\text{175. atm}}$

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350. L

p₂ = ?; V₂ = 2.00 L

Calculation:

$\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}$

8 0

3 years ago

HELPPPPP ME ASAP PLISSSSS​

HELPPPPP ME ASAP PLISSSSS