Answer:
Viscous Drag.
Slab-Pull Force.
Ridge-Push Force
Explanation:
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0.003 moles of NaOH was used in the titration.
<h3>What is titration?</h3>
The concentration of an identified analyte can be found using a simple laboratory technique called titration. As a standard solution with a given concentration and volume, a reagent known as the titrant or titrator is created.
By using a solution with a known concentration to measure the concentration of an unknown solution, this process is known as titration. To a known volume of the analyte (the unknown solution), the titrant (the known solution) is typically added from a buret until the reaction is finished. To ascertain the unknown concentration of an identifiable analyte, titration, commonly referred to as titrimetry, is a widely used quantitative laboratory analytical technique (Medwick and Kirschner, 2010). Volume measurements are a crucial component of titration
Concentration in mol/dm3 =
Amount of solution mol
= concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide
= 0.100 × 0.0250
= 0.00250 mol
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![V=3,5L\\ Cm=0,9M\\ M_{KCl}=74\frac{g}{mol}\\\\ C_{m}=\frac{n}{V}\\\\ n=\frac{m}{M}\\\\ C_{m}=\frac{m}{MV} \ \ \ \Rightarrow \ \ \ m=C_{m}MV\\\\ m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g](https://tex.z-dn.net/?f=V%3D3%2C5L%5C%5C%0ACm%3D0%2C9M%5C%5C%0AM_%7BKCl%7D%3D74%5Cfrac%7Bg%7D%7Bmol%7D%5C%5C%5C%5C%0AC_%7Bm%7D%3D%5Cfrac%7Bn%7D%7BV%7D%5C%5C%5C%5C%0An%3D%5Cfrac%7Bm%7D%7BM%7D%5C%5C%5C%5C%0AC_%7Bm%7D%3D%5Cfrac%7Bm%7D%7BMV%7D%20%5C%20%5C%20%5C%20%5CRightarrow%20%20%5C%20%5C%20%5C%20m%3DC_%7Bm%7DMV%5C%5C%5C%5C%0Am%3D0%2C9%5Cgrac%7Bmol%7D%7BL%7D%2A74%5Cfrac%7Bg%7D%7Bmol%7D%2A3%2C5L%3D233%2C1g)
B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
The letter (d.) strong base or acid would be the most appropriate answer to the question above. An indicator is a strong base or acid. Indicators are strong base and acid because through this you can determine if a compound is acid or base with its color.