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4 years ago

Which statement is most true about a hypothesis?

1 answer:

3 0

This is from dictionary: a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.
I would say it is 2

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Converts 800kg into ng

elixir [45]

Answer:

yes

Explanation:

5 0

3 years ago

At 1000 K, a sample of pure NO2 gas decomposes. 2 NO2(g) equilibrium reaction arrow 2 NO(g) + O2(g) The equilibrium constant KP

kirill115 [55]

Answer: The pressure of NO and $NO_2$ in the mixture is 0.58 atm and 0.024 atm respectively.

Explanation:

We are given:

Equilibrium partial pressure of $O_2$ = 0.29 atm

For the given chemical equation:

$2NO_2(g)\rightleftharpoons 2NO(g)+O_2(g)$

Initial: a

At eqllm: a-2x 2x x

Calculating for the value of 'x'

$\Rightarrow x=0.29$

Equilibrium partial pressure of NO = 2x = 2(0.29) = 0.58 atm

Equilibrium partial pressure of $NO_2$ = a - 2x = a - 2(0.29) = a - 0.58

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{O_2}\times (p_{NO})^2}{(p_{NO_2})^2}$

We are given:

$K_p=158$

Putting values in above expression, we get:

$158=\frac{0.29\times (0.58)^2}{(a-0.58)^2}\\\\a=0.555,0.604$

Neglecting the value of a = 0.555 because it cannot be less than the equilibrium concentration.

So, $a=0.604$

Equilibrium partial pressure of $NO_2$ = (a - 0.58) = (0.604 - 0.58) = 0.024 atm

Hence, the pressure of NO and $NO_2$ in the mixture is 0.58 atm and 0.024 atm respectively.

4 0

3 years ago

If you want to increase the gravitational force between two objects, what would you do

nadezda [96]

There are two things that could be done. The first is to increase the mass of the objects. The second is to decrease the distance between the center of masses of the objects.

6 0

4 years ago

Read 2 more answers

How many moles of co2 are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kpa and a temperature of 50°c?

Rudiy27

Answer:

609 mol

Explanation:

1) Data:

a) n = ?

b) V = 50.0 dm³ = 50.0 liter

c) p = 100.0 kPa

d) T = 50 °C

2) Physical law:

Ideal gas law: pV = nRT,

3) Constants:

R = 0.08206 atm-liter / K-mol

4) Unit conversions:

T = 50 + 273.15 K = 323.15 K

P = 100.0 kPa × (1 amt /101,325 kPa) = 0.9869 atm

5) Solution:

pV = nRT ⇒ n = pV / (RT)

n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)

n = 609 mol ← answer

7 0

3 years ago

Temka [501]

Salt dissolving in water is usually considered to be a physical change so I’m pretty sure it’s that sorry if I’m wrong

6 0

3 years ago