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3 years ago

Find the number of kilometers in 92.25m.

Chemistry

1 answer:

slava [35]3 years ago

4 0

1000m = 1km
92.25m= ?

We cross multiply
92.25/1000
= 0.09225

Therefore, 92.25m = 0.09225km

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How many moles of MgS2O3 are in 223 g of the compound

KengaRu [80]

1.63 moles since 1 mole is equal to 136.4332 grams

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP ONLY HAVE 10 MINUTES. A certain photon of light has a wavelength of 422 x 10 -9 m. What is the frequency of the

Sedaia [141]

Answer:

7.11 x $10^{14}$ Hz

Explanation:

The equation for converting wavelength to frequency is ν=c/λ, or the speed of light over wavelength. The speed of light is 3.00 x $10^{8}$ , and our wavelength here is 422 x $10^{-9}$ . All we have to do now is substitute our given values:

$\frac{3.00x10^{8} }{422x10^{-9}}$

After reduction, our answer comes out to be about 7.11 x $10^{14}$ Hz.

4 0

3 years ago

If a sample of gas is at 672 °C and 3.9 atm, what is the new temperature at 12.2 atm?

Snowcat [4.5K]

In order to calculate the final temperature of the gas, we may apply Charles's law, which states that the pressure and temperature of a fixed amount of gas at constant volume are directly proportional. Mathematically:
P/T = constant
(absolute temperature is used, so T = 672 + 273 = 945 K)
Thus,
3.9 / 945 = 12.2 / T
T = 2,956 K or 2,683 °C

7 0

3 years ago

A gas exerts a pressure of 0.62 atm. Convert this to kPa and mmHg. Be sure to show your work.

IRINA_888 [86]

Answer:

The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg

Explanation:

Data

P = 0.62 atm

P = ? kPa

P = ? mmHg

Process

1.- Look for the conversion factor of atm to kPa and mmHg

1 atm = 101.325 kPa

1 atm = 760 mmHg

2.- Do the conversions

1 atm ----------------- 101.325 kPa

0.62 atm ------------ x

x = (0,62 x 101.325) / 1

x = 62.82 kPa

1 atm ------------------ 760 mmHg

0.62 atm ------------ x

x = (0.62 x 760)/1

x = 471.2 mmHg

4 0

3 years ago

Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one

STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

Density of the octane, ρ = 0.703 g/ml
Volume of octane, v = 3.79 liters

The mass of the octane burnt is calculated as follows;

$m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g$

The combustion reaction of octane is given as;

$2C_8H_{18} + \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O$

From the reaction above:

228.46 g of octane -------------------> 704 g of CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

$= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg$

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0

2 years ago