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White raven [17]
3 years ago
12

Solve the inequality -2x is less than or equal to 3x + 1 is less than or equal to 10

Mathematics
1 answer:
WARRIOR [948]3 years ago
8 0
-2x\leq3x+1\leq10
\frac{-2x-1}{3}  \leq x \leq 3
this is what i understood from what you typed...
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What is 280 million in scientific notation 
Phantasy [73]
The rule of scientifinc notation is that we can use number between 0 and 10, so here we can use 2.8. Lets do this
280 000 000 = 2.8 * 100 * 1 000 000
Now we can just multiply 2.8 by 10 to the power of number of 0 reapeted
So 2.8*10^8 - its the result
3 0
3 years ago
the ratio of students with bikes to students with scooters in the school is 85:51. What is the greatest common factor that you c
Vikentia [17]
Answer:GCF=17

To find the greatest common factor, or GCF, of the numbers, we first need to list the prime factors of both 85 and 51

52=3*17

85=5*17

17 is the sole common factor that these two numbers have in common, therefore 17 is the GCF.

To simplify the ratio, simply divide both numbers by 17.

85:51 becomes 5:3
5 0
3 years ago
Read 2 more answers
Латна монтаж на работа
Bezzdna [24]

Answer:

$183.75

Step-by-step explanation:

divide by 12 (hours)

147/12=12.25

multiply by 15 (hours)

12.25*15=183.75

Hope this helps! :)

4 0
3 years ago
Solve for 15 ≥ -3x or x ≥ -2.
Paladinen [302]

Answer:

x≥−5

Step-by-step explanation:

5 0
3 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
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