All categories

3 years ago

Solve the inequality -2x is less than or equal to 3x + 1 is less than or equal to 10

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

-2x $\leq$ 3x+1 $\leq$ 10
$\frac{-2x-1}{3} \leq x \leq 3$
this is what i understood from what you typed...

You might be interested in

Which represents the solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)?

Nina [5.8K]

1. Simplify the inequality $5.1(3 + 2.2x) > -14.25 - 6(1.7x + 4):$

$15.3+11.22x>-14.25-10.2x-24,\\
15.3+11.22x>-10.2x-38.75.$

2. Separate terms with x and without x in different sides:

$11.22x+10.2x>-38.75-15.3.$

3. Add similar terms:

$21.42x>-54.05.$

4. Divide by 21.42:

$x>-\dfrac{54.05}{21.42} ,\\ \\x>-2.5.$

Answer: correct choice is C.

4 0

3 years ago

Read 2 more answers

Which of these characteristics do a rhombus and a rectangle always have in common?

likoan [24]

Answer: A rectangle has 2 pairs of opposite sides parallel, and four right angles. It is also a parallelogram, since it has two pairs of parallel sides. A rhombus is defined as a parallelogram with four equal sides, which also has 2 pairs of opposite parallel sides.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please answer need help ASAP

9966 [12]

Correct answer is 8. I hope I helped(:

6 0

3 years ago

A class of 64 students was given 320 book. How many will each student take home

Darina [25.2K]

Answer:

Step-by-step explanation:

320 / 64 = 5

7 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%7B%20%5Ccos%5E%7B4%7D%5Calpha%7D%20%5C%3A%20%2B%20%20%20%5Csin%5E%7B2%7D%20%5Calpha%20%5C%

timurjin [86]

Answer:

Proved

Step-by-step explanation:

$cos^4\alpha +sin^4\alpha =\frac{1}{4}(3+cos4\alpha )\\\\$

Take the Left Hand Side:

$cos^4\alpha +sin^4\alpha\\\\(cos^2\alpha )^2+(sin^2\alpha )^2\\\\(\frac{1+cos2\alpha }{2})^2+(\frac{1-cos2\alpha }{2})^2 \\\\\frac{1+2cos2\alpha +cos^22\alpha }{4}+\frac{1-2cos2\alpha +cos^22\alpha }{4} \\\\$

$\frac{1+2cos2\alpha +cos^22\alpha +1-2cos2\alpha +cos^22\alpha }{4} \\\\\frac{2+2cos^22\alpha }{4} \\\\\frac{1+cos^22\alpha }{2} \\\\\frac{1}{2}(1+cos^22\alpha )\\\\$

$\frac{1}{2}(1+\frac{1+cos4\alpha }{2})$

$\frac{1}{2}(\frac{2+1+cos4\alpha }{2})\\\\\frac{1}{4}(3+cos4\alpha )\\\\$

Hence Proved!

The following identities were used are attached in an image

3 0

3 years ago