Answer:
m∠y=72°
Step-by-step explanation:
<u><em>The question is</em></u>
Find the measure of angle y
step 1
Find the measure of angle x
see the attached figure to better understand the problem
we know that
m∠x=67° -----> by corresponding angles
step 2
Find the measure of angle y
we know that
(m∠x+m∠y)+42°=180° -----> because form a straight line
substitute the measure of angle x
67°+m∠y+42°=180
m∠y+108°=180
m∠y=180°-108°
m∠y=72°
Answer:
1 
Step-by-step explanation:
5/3 = 3/3 * 2/3
3/3 = 1
So the answer is 1 
Answer:
17.
Step-by-step explanation:
Statement: "ten more than the product of two and a number"
Translation: 10 + (2 * x)
x = 3.5
10 + (2 * 3.5)
= 10 + 7
= 17.
Hope this helps!
Answer:
Fast ball challenge
Step-by-step explanation:
Given
Slow Ball Challenge




Fast Ball Challenge




Required
Which should he choose?
To do this, we simply calculate the expected earnings of both.
Considering the slow ball challenge
First, we calculate the binomial probability that he hits all 7 pitches

Where
--- pitches
--- all hits
--- probability of hit
So, we have:




Using a calculator:
--- This is the probability that he wins
i.e.

The probability that he lose is:
---- Complement rule


The expected value is then calculated as:


Using a calculator, we have:
Considering the fast ball challenge
First, we calculate the binomial probability that he hits all 3 pitches

Where
--- pitches
--- all hits
--- probability of hit
So, we have:



Using a calculator:
--- This is the probability that he wins
i.e.

The probability that he lose is:
---- Complement rule


The expected value is then calculated as:


Using a calculator, we have:

So, we have:
-- Slow ball
--- Fast ball
<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>
Answer:
The answer is option C
Step-by-step explanation:
f(x) = x³ + 2x² + 3x + 4
To find f(-1) substitute the value of x that's
- 1 into f(x)
That's
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you