Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer:
you again ask your family
Step-by-step explanation:
Ashton has saved: 60% of $120=(60/100)*$120=(60*$120)/100=$72
Ashton need to buy the bike=$120-$72=$48
He needs to buy the bike=$48
X varies directly as y
x = ky
3 = 2k
k =
when x =9
9 =
y
= y
∴y = 6
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