Use this formula (x1+x2 over 2, y1+y2 over 2)
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
Point-slope form is written as : y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point.
The slope (m) is found by the change in Y over the change in X
Slope = (y2 - y1) / (x2 - x1)
You can use either given point for x1 and y1 so you would calculate the slope and replace m with the slope, then replace x1 and y1 in the equation with their value.
Answer:
a) 
b) 
c) 
d) 
e) The intersection between the set A and B is the element c so then we have this:
Step-by-step explanation:
We have the following space provided:
![S= [a,b,c,d,e]](https://tex.z-dn.net/?f=%20S%3D%20%5Ba%2Cb%2Cc%2Cd%2Ce%5D)
With the following probabilities:
And we define the following events:
A= [a,b,c], B=[c,d,e]
For this case we can find the individual probabilities for A and B like this:
Determine:
a. P(A)
b. P(B)
c. P(A’)
From definition of complement we have this:
d. P(AUB)
Using the total law of probability we got:
For this case , so if we replace we got:
e. P(AnB)
The intersection between the set A and B is the element c so then we have this:
