Answer:
2
Step-by-step explanation:
Answer:
N<-7 or (-∞,-7) hope this helps
Answer:
C. Events E and A are independent
Step-by-step explanation:
we will verify each options
(a)
We can use independent events formula
P(B∩C)=P(B)*P(C)
we are given
P(B)=0.4
P(C)=0.25
P(B∩C)=0.05
now, we can plug these values into formula
and we get
0.05=0.4*0.25
0.05=0.1
we can see that left side is not equal to right side
so, this is FALSE
(b)
We can use independent events formula
P(D∩A)=P(D)*P(A)
we are given
P(D)=0.25
P(A)=0.6
P(D∩A)=0.1
now, we can plug these values into formula
and we get
0.1=0.25*0.6
0.1=0.15
we can see that left side is not equal to right side
so, this is FALSE
(c)
We can use independent events formula
P(E∩A)=P(E)*P(A)
we are given
P(E)=0.5
P(A)=0.6
P(E∩A)=0.3
now, we can plug these values into formula
and we get
0.3=0.5*0.6
0.3=0.3
we can see that both sides are equal
so, this is TRUE
(d)
We can use independent events formula
P(D∩B)=P(D)*P(B)
we are given
P(D)=0.25
P(B)=0.4
P(D∩A)=0.15
now, we can plug these values into formula
and we get
0.15=0.25*0.4
0.15=0.1
we can see that left side is not equal to right side
so, this is FALSE
Answer:
Wet Suit Willy found the most treasures per dive.
Step-by-step explanation:
Given:
Diver name Number of dive Number of boxes
Sam 11 33
Wet Suit Willy 18 81
Deep Diving Dan 26 104
Find:
Who found the most treasures per dive
Computation:
Sam's per dive collection = 33 / 11 = 3 boxes
Wet Suit Willy's per dive collection = 81 / 18 = 4.5 boxes
Deep Diving Dan's per dive collection = 104 / 26 = 4 boxes
Wet Suit Willy found the most treasures per dive.
The yearly rate of appreciation is 6,333.3%
(I'm pretty sure I did that right)
