Q2: Mark True or False in the corresponding Answer sheet (0.5 point each)

Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMile

ryzh [129]

Answer:

Following are th program in the C++ Programming Language.

#include <iostream>//set Header files

using namespace std;//set namespace

//define main function

int main()

{

//set integer constants variable

const int NUM_ROWS = 2;

//set integer constants variable

const int NUM_COLS = 2;

//set integer type array

int milesTracker[NUM_ROWS][NUM_COLS];

//set integer type variable and initialize to 0

int i = 0;

//set integer type variable and initialize to 0

int j = 0;

//set integer type variable and initialize to -99

int maxMiles = -99;

//set integer type variable and initialize to -99

int minMiles = -99;

//initialize the value in the two dimensional array

milesTracker[0][0] = -10;

milesTracker[0][1] = 20;

milesTracker[1][0] = 30;

milesTracker[1][1] = 40;

//here is the solution

maxMiles = milesTracker[0][0];

minMiles = milesTracker[0][0];

/*set for loop to find the minimum miles and maximum miles*/

for (i = 0; i < NUM_ROWS; i++)

{

for (j = 0; j < NUM_COLS; j++)

{

//set if condition for maxMiles is the bigger than

if (milesTracker[i][j] > maxMiles)

//initialize milesTracker[i][j] to maxMiles

maxMiles = milesTracker[i][j];

//set if condition for minMiles is the smaller than

if (milesTracker[i][j] < minMiles)

//initialize milesTracker[i][j] to maxMiles

minMiles = milesTracker[i][j];

}

//print output

cout << "Min miles: " << minMiles << endl;

//print output

cout << "Max miles: " << maxMiles << endl;

return 0;

}

Output:

Min miles: -10

Max miles: 40

Explanation:

Here, we define the main method and inside it:

set two constant integer type variable and initialize to 2
set integer type two-dimensional array and pass constant variables in it.
Set two integer type variable and initialize to 0 then, again set two integer type variable and initialize to -99.
Initialize the values in the two-dimensional array.
Set two for loop for the two-dimensional array to find the minimum and maximum miles.
Set two if condition to find bigger or smaller miles.

Finally, print the maximum and the minimum miles then, return 0.

6 0

3 years ago

Write a function maxTemp which takes a filename as string argument and returns the maximum temperature as float type for the wee

Alenkinab [10]

Answer:

#section 1

def maxTemp(filename):

import pathlib

f = pathlib.Path(filename)

f.exists()

if f.exists():

f = open(filename, "r")

#section 2

next(f)

res = [int(sub.split(',')[1]) for sub in f]

maxdata = (res[0])

for i in range(len(res)-1):

if maxdata < res[i]:

maxdata = res[i]

index = res.index(maxdata)

f.close()

#section 3

li = []

a = open(filename, "r")

for line in a:

line = line.strip()

li.append(line)

a.close()

return (li[index+1])

else:

return -1

print(maxTemp("new.csv"))

Explanation:

#section 1:

The function maxTemp is defined. We import pathlib in other to check if the file exists, if it does we carry on with opening the file and if it doesn't the program returns -1.

#section 2:

We start splitting the sub-lists from the second line i.e next(f). For each line we take the second index element and convert it to an integer.

res = [int(sub.split(',')[1]) for sub in f]

The maximum number is gotten by using the if statement to compare all elements in the list. The index of the maximum item in the list is collected.

the file is then closed.

#section 3 :

The file is re-opened and all the lines are striped and passed into a new list and the index recovered from section 2, is used to get the day with the highest temperature and the line is returned.

8 0

3 years ago

What is the magnitude of the largest positive value you can place in a bool? a char? an int? a float?

MaRussiya [10]

Answer:

A bool can hold only true or false values.

A char can hold maximum 65535 characters.

An int can hold maximum positive value of 2,147,483,647.

A float can hold maximum positive value of 3.4 x 10^{38}.

Explanation:

Primitive data types in Java language can be categorized into boolean and numeric data types.

Numeric can be divided further into floating point and integral type. Floating data type includes float and double values while and integral data type which consists of char, int, short, long and byte data types.

Every data type has a range of values it can hold, i.e., every data type has a minimum and maximum predefined value which it is allowed to hold. The intermediate values fall in the range of that particular data type.

Any value outside the range of that particular data type will not compile and an error message will be displayed.

The data types commonly used in programming are boolean, char, int and float.

A boolean variable can have only two values, true or false.

A char variable can hold from 0 to 65535 characters. Maximum, 65535 characters are allowed in a character variable. At the minimum, a char variable will have no characters or it will be a null char variable, having no value.

An int variable has the range from minimum -2^{31} to maximum 2^{31} – 1. Hence, the maximum positive value an int variable can hold is (2^{31}) – 1.

A float variable can hold minimum value of 1.4 x 10^{-45} and maximum positive value of 3.4 x 10^{38}.

The above description relates to the data types and their respective range of values in Java language.

The values for boolean variable remain the same across all programming languages.

The range of values for char, int and float data types are different in other languages.

7 0

2 years ago

Computer science;

leonid [27]

Answer:

Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).

Explanation:

Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).

3 0

3 years ago

Creating a map of your current knowledge is called __________.

poizon [28]

Answer:

D - Concept-mapping

Explanation:

3 0

3 years ago