Question

2.27 LAB: Driving costs Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the gas cost for 20 miles, 75 miles, and 500 miles. Output each floating-point value with two digits after the decimal point, which can be achieved as follows: System.out.printf("%.2f", yourValue);

Answer 1

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation:

Answer 2

Answer:

Java

//////////////////////////////////////////////////////////////////////////

import java.util.Scanner;

public class MyClass {

   public static void main(String args[]) {

     double miles_gallon, gas_gallon;

     ////////////////////////////////////////////////

     System.out.print("Enter miles per gallon: ");

     Scanner myObj = new Scanner(System.in);

     miles_gallon = myObj.nextDouble();

     

     System.out.print("Enter gas dollars per gallon: ");

     gas_gallon = myObj.nextDouble();

     

     System.out.println();

     ////////////////////////////////////////////////

     double twenty_miles = 20/miles_gallon*gas_gallon;

     System.out.printf("Gas cost for 20 miles: $%.2f%n%n", twenty_miles);

     

     double seventy_five_miles = 75/miles_gallon*gas_gallon;

     System.out.printf("Gas cost for 75 miles: $%.2f%n%n", seventy_five_miles);

     

     double five_hundered_miles = 500/miles_gallon*gas_gallon;

     System.out.printf("Gas cost for 500 miles: $%.2f", five_hundered_miles);

   }

}