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3 years ago

Whats the place value of the decimal in the number 125.6

Mathematics

1 answer:

allsm [11]3 years ago

3 0

Answer:

in between the ones and the tenths place

Step-by-step explanation:

so it would be in the ones place

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Round 1.07 to the tenths place.

galben [10]

Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it

5 0

3 years ago

4. Where in the ocean does the water droplet need to be located in order to evaporate?

weeeeeb [17]

Answer:

C or D most likely C

Step-by-step explanation:

Definitely not A or B they don’t matter or make sense.. C makes more sense because it’s directly hit with heat needed to evaporate, for D to be lower it’ll take longer if at all to evaporate because it’s colder closer to the sea floor

3 0

3 years ago

Can anyone do this with steps ..

Harrizon [31]

$\\ \sf\longmapsto \displaystyle{\lim_{x\to 0}}\dfrac{sinx-sin3x}{sins3x-sinx}$

$\boxed{\sf \displaystyle\lim_{x\to 0}\dfrac{f(x)}{g(x)}=\dfrac{\lim_{x\to 0}f(x)}{\lim_{x\to 0}g(x)}}$

Now

$\\ \sf\longmapsto \displaystyle{\dfrac{\lim_{x\to 0}sinx-\lim_{x\to 0}sin3x}{\lim_{x\to 0}sin3x-\lim_{x\to 0}sinx}}$

$\boxed{\sf \displaystyle{\lim_{x\to 0}}f(x)=f(a)}$

$\\ \sf\longmapsto \dfrac{sin0-sin3(0)}{sin3(0)-sin0}$

$\\ \sf\longmapsto \dfrac{0-0}{0-0}$

$\\ \sf\longmapsto \dfrac{0}{0}$

$\\ \sf\longmapsto 0$

7 0

3 years ago

Answer please.. I need help

allsm [11]

9.) 1 / [3]
When you set the denominators of 2 / 5 and 1 / 3, equal to each other, you receive a denominator of 15, the only denominator the two have in common

6 0

3 years ago

These ordered pairs, {(2,4) (3,6) (4,8) (5,10)}, are a function. True False

ki77a [65]

Answer:

True

Step-by-step explanation:

In order for a relation (a set of ordered pairs) to be considered a function, every value in the domain (the set of all the first numbers in the pair) is associated with one value in the range (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if every value in the domain only has one arrow coming out of it. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.

8 0

3 years ago