Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer:
26,250 sq mm^2
Step-by-step explanation:
First i cut the shape so its a rectangle on the top and there is a vertical rectangle. Then you find the lengths and to do that for the first rectangle(the horizontal one) you add 75, 75 and 75 to get the length. Then multiply 225(the sum of the 3 75s) by 75 (width) which gets you 16,875.
That is the area of the first rectangle
Now for the vertical rectangle you simply multiply the length and width, 75x125. That equals 9,375. Now add.
9375+16875= 26250!!!!
N - 7 = 9 if you want it written in equation form
I think you forgot to include that T is the midpoint of SV, but what this would mean is that ST = TV.
5x + 2 = 3x + 12
Subtract 2 from both sides.
5x = 3x + 10
Subtract 3x from both sides.
2x = 10
Divide both sides by 2.
x = 5
Now plug that x into ST.
ST = 5(5) + 2
ST = 25 + 2
ST = 27
