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Montano1993 [528]
3 years ago
7

Help pls I don’t understand this my teacher didn’t teach this

Mathematics
2 answers:
wlad13 [49]3 years ago
5 0

Answer:

Step-by-step explanation:

X=60

aev [14]3 years ago
4 0

Answer:

x = 60

Step-by-step explanation:

The tip of the triangle's angle is 100 (b/c 180-80)

x + 100 + 20 = 180

x + 120 = 180

x = 60

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Find tan A<br><br> Help please
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3 years ago
Select the property that allows the left member of the equation to be changed to the right member.
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5 0
3 years ago
Read 2 more answers
Question
Kay [80]

Answer:

f(x)=2(x-2)(x^2+64)

Step-by-step explanation:

A standard polynomial in factored form is given by:

f(x)=a(x-p)(x-q)...

Where <em>p</em> and <em>q</em> are the zeros.

We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.

First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.

Therefore, we acquire:

f(x)=a(x-(2))(x-(-8i))(x-(8i))

Simplify:

f(x)=a(x-2)(x+8i)(x-8i)

Expand the second and third factors:

=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64

Hence, our function is now:

f(x)=a(x-2)(x^2+64)

It equals 320 when <em>x</em> = 4. Therefore:

320=a(4-2)(4^2+64)

Solve for <em>a</em>. Evaluate:

320=(2)(80)a

So:

320=160a\Rightarrow a=2

Our third-degree polynomial equation is:

f(x)=2(x-2)(x^2+64)

7 0
3 years ago
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