We are given statement : 3 more than a number then divided the result by 8.
We need to write an algebraic expression for it.
Let us assume unknown number be n.
3 more than n = (n+3).
Now, we need to divide that result (n+3) by 8.
So, we would get (n+3) divided by 8 = 
.
<h3>Therefore, final expression is
</h3>
Answer:
et's solve for x.
5y−4x=−72y+4z
Step 1: Add -5y to both sides.
−4x+5y+−5y=−72y+4z+−5y
−4x=−77y+4z
Step 2: Divide both sides by -4.
−4x
−4
=
−77y+4z
−4
x=
77
4
y−z
Answer:
x=
77
4
y−z
Let's solve for y.
5y−4x=−72y+4z
Step 1: Add 72y to both sides.
−4x+5y+72y=−72y+4z+72y
−4x+77y=4z
Step 2: Add 4x to both sides.
−4x+77y+4x=4z+4x
77y=4x+4z
Step 3: Divide both sides by 77.
77y
77
=
4x+4z
77
y=
4
77
x+
4
77
z
Answer:
y=
4
77
x+
4
77
z
Step-by-step explanation:
I think that can help :) wanna chat add me as friend
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
Answer:
2
Step-by-step explanation:
7+2n = 11
2n = 11-7
2n = 4
n = 4/2
therefore n = 2
Answer:
The function f(x) has a vertical asymptote at x = 3
Step-by-step explanation:
We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.
For example, in the case of the natural logarithm, it is not defined for x = 0.
Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)
So a vertical asymptote will be a vertical tendency at a given x-value.
In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)
Then:
The function f(x) has a vertical asymptote at x = 3
