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pantera1 [17]
3 years ago
12

PLEASE HELP! I'M STUCK! ps I only have on shot please only answer if u know the correct answer

Mathematics
2 answers:
kogti [31]3 years ago
5 0

Answer:

1/9

Step-by-step explanation:

i already answered this in a different thread. here it is again. Also congrats on being on the top five brainliest users of the day! (today is 11/30/2020)

Sophie [7]3 years ago
3 0

Answer:

1/9

Step-by-step explanation:

Plug in the values of a, b, and c

1^3+3^2+5/1+3^2+5^3

1+9+5/1+9+125

15/135

simplify

1/9

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Step-by-step explanation:

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4 years ago
Use the method of cylindrical shells to write out an integral formula for the volume of the solid generated by rotating the regi
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Answer:

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Step-by-step explanation:

Please find the graph file.

h= y=2x-x^2\\\\r= x\\\\Area=2\pi\times r\times h\\\\= 2 \pi \times x \times (2x-x^2)\\\\= 2 \pi \times 2x^2-x^3\\\\volume \ V(x)=\int \ A(x)\ dx\\\\= \int^{x=1}_{x=0} 2\pi (2x^2-x^3)\ dx\\\\= 2\pi [(\frac{2x^3}{3}-\frac{x^4}{4})]^{1}_{0} \\\\= 2\pi [(\frac{2}{3}-\frac{1}{4})-(0-0)] \\\\= 2\pi \times \frac{5}{12}\\\\=\frac{5\pi}{6}\\\\

3 0
3 years ago
Divide 12 x²y²z by 6xyz​
mafiozo [28]

Answer:

2xy

Step-by-step explanation:

6 0
3 years ago
What is -5(3-2g) equal
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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HELP PLEASE! Will give the Brainliest if shown work!!
scZoUnD [109]

Answer:

\large\boxed{Q1.\ A_{\triangle PQR}=90\ cm^2}\\\\\boxed{Q2.\ V\approx321\ m^3}

Step-by-step explanation:

Q1.\\\\\text{If}\ \triangle ABC\sim\triangle PQR\ \text{then the quotient of the areas is equal}\\\text{the square of the similarity scale}\ k.\\\\\text{The sides}\ AB\ \text{and}\ QP\ \text{are corresponding}.\ \text{Calculate the scale:}\\\\k=\dfrac{4}{6}=\dfrac{4:2}{6:2}=\dfrac{2}{3}\\\\\text{The area of }\ \triangle ABC=40\ cm^2.\\\\\text{Let the area of}\ \triangle PQR=x,\ \text{then}\\\\\dfrac{40}{x}=\left(\dfrac{2}{3}\right)^2\\\\\dfrac{40}{x}=\dfrac{4}{9}\qquad\text{cross multiply}\\\\4x=(9)(40)\qquad\text{divide both sides by 4}\\\\x=(9)(10)\\\\x=90\ cm^2

Q2.\\\\\text{The formula of a volume of a sphere:}\\\\V=\dfrac{4}{3}\pi R^3\\\\R-radius\\\\\text{We have the diameter}\ 2R=8.5\ m\to R=\dfrac{8.5}{2}\ m=4.25\ m.\\\\\text{Substitute:}\\\\V=\dfrac{4}{3}\pi(4.25)^3=\dfrac{4}{3}\pi(76.765625)=(4)(25.588541)\pi=102.354164\pi\\\\\pi\approx3.14\\\\V=(102.354164)(3.14)\approx321\ m^3

8 0
3 years ago
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