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gogolik [260]
3 years ago
9

Difference between 1 8/10 and 2 2/5

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0
The first step to solving this is converting these mixed numbers into improper fractions. You would do that by multiplying the denominator by the whole number and adding the numerator to that number; this number replaces the numerator. It would look something like this:

1 8/10   -->   18/10
2 2/5   -->   12/5

Now, to subtract the second fraction from the first one, the denominators of both fractions must be the same. We can make them the same by multiplying the second fraction by 2:

12/5 * 2/2 = 24/10

Now we can set up the equation as:

18/10 - 24/10 = -6/10   -->   -3/5

The answer is negative 3/5.

I hope this helps.
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Answer:

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If you were asking how many miles in the <u>2 hours</u>: 122 miles

Step-by-step explanation:

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3 years ago
Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)?
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Answer:

y = 1/12 (x − 5)²

Step-by-step explanation:

We can solve this graphically without doing calculations.

The y component of the focus is y = 3.  Since this is above the directrix, we know this is an upward facing parabola, so it must have a positive coefficient.  That narrows the possible answers to A and C.

The x component of the focus is x = 5.  Since this is above the vertex, we know the x component of the vertex is also x = 5.

So the answer is A. y = 1/12 (x−5)².

But let's say this wasn't a multiple choice question and we needed to do calculations.  The equation of a parabola is:

y = 1/(4p) (x − h)² + k

where (h, k) is the vertex and p is the distance from the vertex to the focus.

The vertex is halfway between the focus and the directrix.  So p is half the difference of the y components:

p = (3 − (-3)) / 2

p = 3

k, the y component of the vertex, is the average:

k = (3 + (-3)) / 2

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And h, the x component of the vertex, is the same as the focus:

h = 5

So:

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3 years ago
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. Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at
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<u>Answer:</u>

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<u>Solution:</u>

We know \text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }

Anne is pushing the wheelbarrow with a force of 70 N at an angle of 50^{\circ} with the horizontal

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