Answer:
Area of the sector = 29.48 square miles.
Step-by-step explanation:
Given:
Radius of a circle = 13 miles
Angle bounded by the arc = 20 deg
To find
Area of the sector bounded by 20 degrees.
Note: Area of a sector =
Plugging the values in the equation.
⇒ 
⇒ 
⇒
square-miles
So the area of the sector bounded by 20 degree arc is 29.48 square miles.
The answer is 18/5 and simplify that and u get 3 3/5.
You could first solve for y, assuming x is 0, and y = 6. Then solve for x, and that means y = 4.
Answer:
<em>The ball's speed will be 10 m/s at t=1.22 seconds</em>
Step-by-step explanation:
The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.
If the object is thrown upwards at speed vo, its speed at time t is:

Where g is the acceleration of gravity 
Our ball is thrown upwards with v0=22 m/s. We need to calculate the time when its speed is vf=10 m/s.
Solving the above equation for t:

Substituting:

t=1.22 seconds
The ball's speed will be 10 m/s at t=1.22 seconds