B. Mark bought 4 packs of gum for $1.5 each. 6 dollars in total. The 4 packs of gum is on the x axis (x, y) and the the total is 6 dollars.
Y-intercept =12
Slope : y2-Y1/x2-x1
8-10/2-1
Slope : -2
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
21+4(32-5)=448
I think it’s 448
A ratio of 11x to 10x
Where x is a number to keep the ratio the same.
Perimeter = 84
Perimeter = 2 (Length + breadth)
84 = 2 ( 11x + 10x)
84 = 2(21x)
21x = 42
x=2
So that means the actual length of the sides would be:
11 x 2 : 10 x 2
22 : 20
So that means the length can be 22, and the breadth will be 20.
Or the length is 20, and the breadth is 22.
