Prove that: sin8A/1-cos8A=cot4A
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So hmm notice the picture below
the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges
now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both
the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges
now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both