Given that :
log3=0.477 , log4=0.602 and log5=0.699
Now , as you know that
We have to find the value of
So,=
= 
Now Putting the values of log3, log4 and log5 in the above expression
=1.0079/0.699
=1.5436..
=1.544 (approx)
So, the value of is 1.544(approx).
Answer:
AD=5
Step-by-step explanation:
We are given that
AB=10, AC=6 BC=6
We have to find the value of AD.
Let AD=x
BD=AB-AD
BD=10-x
Credits to: lublana
Step-by-step explanation
Answer:
Enlargement.
Scale Factor: 3
Step-by-step explanation:
Use points to find the enlargement. Typically, you will use all the points.
A(1 , 1) ⇒ A'(3 , 3)
B(2 , 1) ⇒ B'(6 , 3)
C(1 , 2) ⇒ C'(3 , 6)
D(2 , 2) ⇒ D'(6 , 6)
To find the scale factor, simply divide the Point' with the original Point. Use any number.
A'(3 , 3)/(A(1 , 1)) = 3
B'(6 , 3)/(B(2 , 1)) = 3
C'(3 , 6)/(C(1 , 2)) = 3
D'(6 , 6)/(D(2 , 2)) = 3
Your scale factor is 3.
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Answer:
1. Option A
2. Option B
Step-by-step explanation:
I would like to elaborate on the answer to the second question, since the first answer is actually option a. Why? The question asks for a parametric equation, not set, so it would be choice a.
2. x=3t + 5 - isolate t
t=(x-5)/3 - substitute into the second equation
y = [(x-5)/3]^2 - 1
your solution is option b
Answer: 5
Step-by-step explanation: 4 + 3 + -2 = 5
