$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$

8 0

4 years ago

PLEASE, IT IS URGENT!!!!!!!!!!!!!!!!

sasho [114]

Convert the timing into hours only:
11:15 = 11.25h
9:45 = 9.75h
11:45 = 11.75h
7:45 = 7.75h
10:45 = 10.75h

To find the average, we need to find the middle of these timing:
11.25 + 9.75 + 11.75 + 7.75 + 10.75 = 51.25

51.25 ÷ 5 = 10.25h = 10:15 am

------------------------------------------------------------------------
Answer: The average time it docks is 10:15 am.
------------------------------------------------------------------------

5 0

3 years ago

Solve using the quadratic formula. Write answers as an exact value and as a decimal rounded to the nearest hundredth.

vichka [17]

Answer:

$\frac{-2±\sqrt{3} }{2}$

dec form: -0.13

Step-by-step explanation:

4 0

3 years ago