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irina [24]
3 years ago
11

You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:A

Step-by-step explanation: 10/37

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Solving these quadratics for x using complete the square 3x^2-4x-1=0
ZanzabumX [31]

Answer:

in picture

Step-by-step explanation:

5 0
3 years ago
Using the provided table, calculate the effective tax rate for a single taxpayer with a taxable income of $52,000.
barxatty [35]

Answer:

Option C is correct ,14.2%

Step-by-step explanation:

In order to determine the effective tax rate of a taxpayer with taxable income of $52,000,the starting point to determine how much in taxes the taxpayer pays as shown below:

First tax bracket=$9,525*10%=$952.5

Second tax bracket=$952.50+(12%*($38700-$9,525))

                                =$952.50+$3501

Third tax bracket(where the taxpayer belongs)=4453.5 +(22%*($52,000-$38,700))

third tax bracket tax=4453.5+$2926 =$7379.5

Since the total tax payable of  $7379.5   is now computed,

effective tax rate=tax paid/taxable income=7379.5/52000 =14.2%

7 0
3 years ago
Read 2 more answers
59.952 nearest tenth
Aleonysh [2.5K]
59.952 in the nearest tenth is 60
5 0
2 years ago
Read 2 more answers
Helpp!!! This is due Sunday. I don’t understand!
Darya [45]

Answer:

11, 15, 26, 41, could be an answer


6 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
9 months ago
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