We know that
[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube
The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=<span>5 cm
T</span>he biggest block was 729 cm³------> b3=√729------> b3=<span>9 cm
[</span><span>the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm
</span><span>
the answer is
</span>the stack of blocks was 18 cm tall<span>
</span>
Nope.
They don't meet the requirements of the triangle inequality.
2.1 + 4 = 6.1 < 7.9
The triangle inequality requires the sum of any two sides be greater than the third side.
Area of sector is 17.584 meters
<em><u>Solution:</u></em>
Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m
Diameter = 12 m
Radius = Diameter / 2 = 6 m
An angle of 56 degrees is the fraction
of the whole rotation
A sector of a circle with a sector angle of 56 degrees is therefore also the fraction
of the circle
The area of the sector will therefore also be
of the area

Thus area of sector is 17.584 meters