Write the expression. Then, complete the statements.

Which of the following are considered measures of center? I. mean II. median III. interquartile range A. III only B. I and II on

andrezito [222]

Answer: Choice B) I and II only

The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.

4 0

3 years ago

Find the variable. m angle BDJ=7y+2 , m angle JDR=2y+7

Anna35 [415]

The value of the variable y is 9 given that BDJ=7y+2 and angle JDR=2y+7

From the attached diagram, we can see that the sum of m<BDJ and m<JDR is complementary (i.e. sums up to 90degrees)

Given the following

m<BDJ = 7y + 2

m<JDR = 2y + 7

Summing up to 90

m<BDJ + m<JDR = 90

7y + 2 + 2y + 7 = 90

7y+2y+2+7 = 90

9y + 9 = 90

9y = 90-9

9y = 81

y = 81/9

y = 9

Hence the value of the variable y is 9

Learn more here: brainly.com/question/17247176

3 0

3 years ago

HELP ASAP RN PLEASE!! 200 people got an email 37 people clicked on it how do you get 18.5%

son4ous [18]

Answer:

37/200

Step-by-step explanation:

Event/Sample Space = .185 = 18.5%

7 0

3 years ago

Read 2 more answers

Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour, start at the same place and run along t

Vikentia [17]

Answer:

The Distance cover by both the Runners is same = 10 miles

Step-by-step explanation:

According to question ,

The Speed of first runners (S 1) = 5 miles per hour

The speed of second runners (S 2) = 4 miles per hour

Let The Time taken by First runner (T 1 ) = T hour

But the second runner arrives half hour after the first runner ,

I.e The Time taken by Second runner (T 2) = ( T + $\frac{1}{2}$ )

Now from Distance = Speed × Time

Since both the runners start from same place and run along the same trail

SO ,Both the Distance cover by both are same , D 1 = D 2

i.e Speed 1 × Time 1 = Speed 2 × Time 2

5 mph × T = 4 mph × ( T + $\frac{1}{2}$ )

5 T = 4 T + ( 4 × $\frac{1}{2}$ )

Or, 5 T - 4 T = 2

∴ T = 2 hour ,

Time take by first = T1 = T = 2 hour

Time take by second = T2 = T + $\frac{1}{2}$ = (2 + $\frac{1}{2}$ )hour = $\frac{5}{2}$

Now the Distance cover = Speed × Time

Distance (D1) = 5 mph × 2 hour = 10 mile

And Distance (D2) = 4 mph × $\frac{5}{2}$ = 10 miles

Hence, As The Distance cover by both the Runners is same = 10 miles Answer

5 0

4 years ago

HELP ME PLWASE ITS A TEST

cupoosta [38]

Answer:

1/3 you will add it to get your main description and get your final answer

4 0

3 years ago