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skelet666 [1.2K]
3 years ago
7

Gavyn was thinking of a number.gavyn halves it and gets an answer of 9.4 what was the original number?

Mathematics
1 answer:
kupik [55]3 years ago
3 0
Answer:

18.80

Explanation:

All you have to do is add 9.4 to 9.4, or multiply 9.4 times 2, and you get 18.80
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A new bank customer with ​$2,000 wants to open a money market account. The bank is offering a simple interest rate of ​%1.1a. Ho
Goshia [24]

Answer:

$2220

Step-by-step explanation:

Step one

Given data

Principal= $2000

rate= 1.1%= 0.011

time= 10 years

<u>Required</u>

<u>The final amount A</u>

Step two;

For simple interest, the final amount is given as

A=P(1+rt)

substitute

A=2000(1+0.011*10)

A=2000(1+0.11)

A=2000(1.11)

A=2220

$2220

5 0
2 years ago
Please very urgent!!!
OleMash [197]

Answer:

216

Step-by-step explanation:

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7 0
3 years ago
1.3.2 - Harry has a 14 foot pole. He cuts off 4 1/2 feet of it and then cuts off
Evgen [1.6K]

Answer:

9.31 is what I got

So 9.31 feet

Step-by-step explanation:

8 0
2 years ago
Find how X and y compare when log X = 6.6 and log y = 3.6
asambeis [7]

Answer

x = 3981071.7055

y  = 3981.0717

x > y

Step by step explanation

First let's find the value of x and y by taking anti - log.

log X = 6.6

X = log^ -1 (6.6)

X = 3981071.7055

Similarly,

log Y = 3.6

Y = log ^(-1) 3.6

Y = 3981.0717


Once we found the values of X and Y , we can easily compare them.

Here x > y

Hope you will understand the concept.

Thank you. :)

8 0
3 years ago
Given: BD bisects ABC. Auxiliary EA is drawn such that AE || BD. Auxiliary BE is an extension of BC
AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} &#10; Statement & Reason \\ [1ex] &#10;1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\&#10;2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ &#10;3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ &#10;4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\&#10;5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ &#10;6. \angle ABD\cong\angle BAE & 6. Alternate angles&#10;\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}&#10;7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\&#10;8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\&#10;9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\&#10;11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] &#10;\end{tabular}&#10;
7 0
3 years ago
Read 2 more answers
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