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frozen [14]
3 years ago
12

A machine fills bags with sweets.

Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0

Answer:

19

Step-by-step explanation:

maximum no. of bag filled by 4275 sweets,is

4275/28 ~=152

therefore , there is 4256 sweets in 152 bags

therefore,4275-4256=19 sweets are left

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HURRY I NEED THIS BEFORE 12
I am Lyosha [343]
X=8 because add 11 to both sides and it becomes 28=3.5x and divide both sides by 3.5 so x=8
5 0
3 years ago
HELP PLSS
atroni [7]

The balloon reaches a height of 7 feet at 0.1 seconds and 2.13 seconds

<h3>How to determine the time the balloon is at the height?</h3>

The equation of the function is given as

h(t)= -16t^2 + 35t + 5

The above equation is a quadratic equation

When the balloon is at a height of 7 feet, we have

h(t) = 7

So, we have the following equations

h(t)= -16t^2 + 35t + 5

h(t) = 7

Next, we plot the equations on a graph (see attachment)

The equations intersect at

t = 0.059 and t = 2.129

Approximate

t = 0.1 and 2.13

Hence, the times are 0.1 seconds and 2.13 seconds

Read more about quadratic equation at

brainly.com/question/15709421

#SPJ1

8 0
1 year ago
Can someone help me with this
Olin [163]

Answer:

6

Step-by-step explanation:

If p equals 15 then plug 15 in for p and take 15-9=6. pretty sure that's what they are looking for there.

5 0
3 years ago
Read 2 more answers
Can you answer 14.15.16
Ne4ueva [31]

Answer:

can you please tell me the question there's nothing there

Step-by-step explanation:

8 0
3 years ago
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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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