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inessss [21]
3 years ago
10

1q - 2x = 7 What is x please im so stuck on this i will give brainliest

Mathematics
2 answers:
Tems11 [23]3 years ago
8 0

Answer: x

=

4

Step-by-step explanation:

REY [17]3 years ago
6 0
Solve for x
Move all terms that don't contain
x to the right side and solve.

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Eleanor and max used two rectangular wooden boards to make a set for the school play.one board was 6 feet long and the other boa
Oksi-84 [34.3K]

By definition, the area of a rectangle is:

A = w * l

Where,

w: width of the rectangle

l: length of the rectangle

The total area is given by:

A = A1 + A2

Where,

A1: rectangular wooden board 1

A2: rectangular wooden board 2

Substituting we have:

60 \frac{3}{8} = (6) (w) + (5\frac{1}{2}) (w)

Rewriting we have:

\frac{483}{8} = (6) (w) + (\frac{11}{2}) (w)

483 = 48w + 44w\\483 = 92w

w = \frac{483}{92}\\w = 5.25

 w = 5 \frac{1}{4}

Answer:

The width is given by:

w = 5 \frac{1}{4}

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3 years ago
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Solve the inequality. Graph the solution set and write it in interval notation 4x-4<6x+4
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4. If some of Tucson's residents have blue eyes and some of Tucson's residents are children, is the statement "Some of Tucson's
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Answer: <span>unsubstantiated.

This is, the statement </span><span>"Some of Tucson's residents are blue eyed children" cannot be inferred from the two original statements.

Because the subset of </span><span>"Tucson's residents that have blue eyes" and the subset of "Tucson's residents that are children" might or might not have common elements.</span>
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Which of the following functions has two zeros at (−4, 0), (1, 0), and a y-intercept at (0,−2)?
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3 years ago
Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain wei
yawa3891 [41]

Answer:

The result indicates that the percentage of all samples of three men that have mean brain weights within (1.24 * sampling error) of the mean is 78.50%.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

According to one study, brain weights of men are normally distributed with mean = 1.20 kg and a standard deviation = 0.14 kg.

Determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.20 kg. Interpret your answer in terms of sampling error.

The explanation of the answers is now provided as follows:

Based on the Central limit theorem, it possible to say that the mean of sampling distribution (μₓ) is approximately equal to the population mean (μ) as follows:

μₓ = μ = 1.20 kg …………………………. (1)

Also, the standard deviation of the sampling distribution can be written as follows:

σₓ = (σ/√N) ……………………….. (2)

Where:

σ = population standard deviation = 0.14 kg

N = Sample size = 3

Substituting the values into equation (2), we have:

σₓ = 0.14 / √3 = 0.0808

Since we are to determine the percentage of all samples of three men that have mean brain weights within 0.1 kg of the population mean brain weight of 1.20 kg, this implies that we have:

P(1.10 ≤ x ≤ 1.30)

Therefore, 1.10 and 1.30 have to be first normalized or standardized as follows:

For 1.10 kg

z = (x - μₓ) / σₓ = (1.10 - 1.20) / 0.0808 = -1.24

For 1.30 kg

z = (x - μₓ)/σₓ = (1.30 - 1.20) / 0.0808 = 1.24

The required probability can be determined when P(1.10 ≤ x ≤ 1.30) = P(-1.24 ≤ z ≤ 1.24).

From the normal distribution table, the following can be obtained for these probabilities:

P(1.10 ≤ x ≤ 1.30) = P(-1.24 ≤ z ≤ 1.24) = P(z ≤ 1.24) - P(z ≤ -1.24) = 0.89251 - 0.10749 = 0.7850, or 78.50%

Therefore, the sampling error is equal to 0.0808 which is the standard deviation of the sampling distribution.

In terms of the sampling error, the result indicates that the percentage of all samples of three men that have mean brain weights within (1.24 * sampling error) of the mean is 78.50%.

3 0
3 years ago
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