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sammy [17]
3 years ago
13

Find the area of this parallelogram. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

A=BH so, Area is 108 inches :)

Step-by-step explanation:

A= B x H

A = 12 x 9

A = 108

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a total of 677 tickets were sold for the school play they were either adult tickets or student tickets there were 73 fewer stude
QveST [7]

Answer:

375 adult tickets and 302 student tickets

Step-by-step explanation:

s+a=677

a=s+73

s+s+73=677

2s+73=677

2s=604

s=302

a= 375

7 0
3 years ago
pls help Isabella is saving up money to buy a car. Isabella puts $7,000.00 into an account which earns 3% interest, compounded m
Aleksandr [31]

Answer:

$1,050

Step-by-step explanation:

√Verified.

4 0
3 years ago
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What is the surface area of a rectangular prisim with dimensions 5ft, 6ft, and 7ft.
djyliett [7]

Ok the formula for this is 2(lw +hw+hL)

2(30+35+42)=2(107)=214 square feet

8 0
2 years ago
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23. What is the equation of the line that contains the points (2, 1) and (-1, -8)?
Sauron [17]
I'm guessing this is a slope problem, so the equation would be like this: y = mx + b where m is the slope and b is the y-intercept.

m =  \frac{y1 - y2}{x1 - x2}
Using this,
m =  \frac{1  + 8}{2  + 1}  =  \frac{9}{3}
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6 0
3 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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