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Katena32 [7]
3 years ago
9

Determine if the following statement is true or false.​ Why? The expected frequencies in a​ chi-square test for independence are

found using the formula below.
Expected frequency = (row total)(column total) / table total
Choose the correct answer below.
1. False. This formula gives the expected proportion. The (table total) factor in the denominator on the right should be squared.
2. True. It is a simplification of multiplying the proportion of a row variable by the proportion of the column variable to find the proportion for a cell, then multiplying by the table total.
3. True. The area to the right of this value in the corresponding chi-square distribution gives the P-value for the test.
4. False. The expected frequencies for a chi-square test are given by Oi - Ei/ Ei where i represents cell number.
Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Download docx
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Interpret the following sine regression model.
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Answer:

The question is incomplete, so I will describe the sine regression model.

The function

y = 0.884 sin(0.245x - 1.093) + 0.400

correspond to the general equation:

y = a sin(bx - c) + d

where:

a = 0.884

b = 0.245

c = 1.093

d = 0.400

The amplitude of the function is computed as follows:

amplitude = |a| = 0.884

The period of the function is computed as follows:

period = 2π/|b| = 25.6456

The phase shift of the function is computed as follows:

phase shift = c/b = 4.4612 to the right (because there is a minus sign before c in the equation)

The vertical shift of the function is computed as follows:

vertical shift = d = 0.400

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Step-by-step explanation:

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3 years ago
A distribution of measurements is relatively mound-shaped with a mean of 40 and a standard deviation of 15. Use this information
MArishka [77]

Answer:

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 40

Given that standard deviation of the Population = 15

Let 'x' be the random variable in normal distribution

Let 'X' = 25

Z = \frac{x-mean}{S.D} = \frac{25-40}{15} = -1

Let 'X' = 55

Z = \frac{x-mean}{S.D} = \frac{55-40}{15} = 1

<u><em>Step(ii):-</em></u>

The probability that between 25 and 55

P( 25 ≤ X≤ 55) = P( -1≤z≤1)

                       = A(1) - A(-1)

                      = A(1) + A(1)

                     = 2 × A(1)

                    = 2× 0.3413

                   = 0.6826

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

<u><em>Final answer:-</em></u>

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

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Answer:

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