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Aleksandr [31]
3 years ago
6

Express as a single power.

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0

a) 1

b) -5

c) \frac{6^3.6^5}{6^2.6^4} = \frac{6^{3+5} }{6^{2+4} } = \frac{6^8}{6^6} = 6^{8-6}=6^2

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How to arrow way 700-456=
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The answer to this is 244
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$3 for 6 bagels; $9 for 24 bagels.Determine if the rates or ratios are equivalent
Luba_88 [7]
No these are not equivelent.  24 is 4x6 so that would mean that you would have to pay $12 for those bagels and because 9 is not 3x4, 12 is making these two ratios not equivelent.

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Examine the following sequence 1, 4, 9, 16, 25…. Why is 36 the next number in the sequence? Because the pattern is: a. Add the n
Nata [24]
<span>B. Square the number of the term, n</span>
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4 years ago
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A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
The first three steps in determining the solution set of the system of equations, y = –x2 – 2x + 8 and y = 2x + 11, algebraicall
shutvik [7]
First step
Using substitution you can fill 2x + 11 in for the y part of the first equation
This will look like: 2x + 11 = -x^2 -2x + 8

Second step
Now we need to solve for the variable by combining like terms you can start by adding x^2 + 2x -8 to both sides
You get 0 = x^2 +4x +3

Third step
Factor
(X+3)(x+1)=0

If you need the y values you can fill in x= -3 to the second equation y= 2(-3) + 11 and y=5
First point is (-3,5)

The other point is found by filling x=-1 into the second equation: y= 2(-1) +11 and y = 9
Second point is (-1,9)
5 0
3 years ago
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