PLZ HURRY IT'S URGENT!!!

1/4 es un decimal exacto

expeople1 [14]

Answer:

0.25

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Dkendbdjdbebdbdbdjdnd

sertanlavr [38]

Answer:

5/2

Step-by-step explanation:

The 5^-3 and 5^6 cancel out to be 5^3. Then the 5^3 cancels out with the 5^2 in the denominator and leaves you with just a 5. The 2^2 makes the 2^3 in the denominator just 2. So, you are left with 5/2! Hope this helps.

7 0

2 years ago

Someone must have beaten me here. Devora thinks, dismayed by the empty treasure chest. Then, just as she's about to close the li

Sidana [21]

Answer:

she turned 82 degrees.

Step-by-step explanation:

Suppose, the unknown angle is A

Now, we know that according to the sine law ,

the ratio of side of a triangle and the sine value of the angle opposite to that side is same . It says that,

if a triangle has 3 sides a,b and c and 3 angles A,B,and C and they are opposite to the sides respectively then,

a/SinA=b/sinB=c/SinC

check the image below in attachment.

From the diagram at attachment.

here , angle A is required.

given, angle C= 30

side b=89 m and c= 48 m

sin law says a/sinA=b/sinB=c/sinC

first we take , b/sinB=c/sinC

or, 89/sinB= 48/sin30

or, sinB=( 89×0.5)/48 =0.92

or, B=68

we know, in every triangle , the sum of 3 angles of a triangle is 180

then, A+B+C=180

or, A=180-B-C= 180 - ( B+C)

=180-(68+30)

or, A = 82

therefore , the required angle is 82 degree.

she turned 82 degrees.

8 0

3 years ago

Claire and her partner, Grace, are throwing for the javelin event as a team. Claire threw the javelin 42 ft. and Grace threw it

Blababa [14]

Answer:

42+39 or 81 feet

Step-by-step explanation:

add them up and you get 81 feet.

Hope this helps plz hit the crown :D

4 0

2 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

2 years ago