$Distribute\:parentheses\\=xx^2+x\left(-2x\right)+x\left(-3\right)+\left(-4\right)x^2+\left(-4\right)\left(-2x\right)+\left(-4\right)\left(-3\right)\\\mathrm{Apply\:minus-plus\:rules}\\+\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab\\=x^2x-2xx-3x-4x^2+4\cdot \:2x+4\cdot \:3\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\x^2x=\:x^{2+1}=\:x^3\\=x^3\\2xx\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\xx=\:x^{1+1}=\:x^2\\=2x^2\\4\cdot \:2x\\\\=8x\\$

$4\cdot \:3\\\mathrm{Multiply\:the\:numbers:}\:4\cdot \:3=12\\Group\:like\:terms\\=x^3-2x^2-4x^2-3x+8x+12\\\mathrm{Add\:similar\:elements:}\:-3x+8x=5x\\=x^3-2x^2-4x^2+5x+12\\\mathrm{Add\:similar\:elements:}\:-2x^2-4x^2=-6x^2\\=x^3-6x^2+5x+12\\Answer: =x^3-6x^2+5x+12$

4 0

3 years ago

A triangle has one angle of 120 degrees what must be true about the other two angles A- the sum of the two angles must be equal

lara31 [8.8K]

Answer:

Step-by-step explanation:

A triangles sum of all the angles will be 180, so since we already have one as 120, then that least 60. So the sum of the two extra angles has to be 60.

6 0

2 years ago

A village was founded four hundred years ago by a group of 20 people. In this village, the population triples every one hundred

sp2606 [1]

Answer:

after four years there is 1630 people in the village.

Explanation:

sorry if it is wrong

4 0

2 years ago