Answer:
Step-by-step explanation:
3x+7y-2x+3y+7
group like terms
3x-2x +7y+3y +7
x+10y+7
answer = the elder bother is 17 and the younger one is 15
constructive odd integers= 15 and 17
17×15= 255
255+38 = 293
Square root of 293 = 17
10+2(x)=5(x-7)
10+2(x)=5(x)-35
35+10=5(x)-2(x)
45=3(x)
45/3=x
x=15
Answer:
105/330 = 21/66 = 7/22
7/22 is the answer I think
Step-by-step explanation:
n(U) = 330
n(A) = 85
n(B) = 200
n(A n B) = 60
Now,
n(A U B) = n(A) + n(B) - n(A n B)
or, n(A U B) = 85 + 200 - 60
or, n(A U B) = 285 - 60 = 225
Now,
n(A U B) compliment = n(U) - n(A U B)
n(A U B) compliment = 330 - 225
so, n(A U B) compliment = 105
Now,
probability = 105/330
Median: 3
mode: 3
range: 9
interquartile range: 2
the outliers are 9 and 5. there is a cluster between 2 and 3.
