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Vilka [71]
3 years ago
14

Help!!!! I really need help with this I don’t understand it!!!

Mathematics
1 answer:
Temka [501]3 years ago
6 0

9514 1404 393

Answer:

  y = 5

Step-by-step explanation:

There are a number of ways to get there, but the short of it is that a horizontal line has the equation ...

  y = constant

The constant value must be chosen to match the y-value of points on the line. Here, that is 5. The equation of the line is ...

  y = 5

_____

<em>Another way</em>

You can write the equation in slope-intercept form if you know the slope and the y-intercept. The line crosses the y-axis at y = 5, so that is the value of the y-intercept.

The "rise" between the two points is 5 -5 = 0. The "run" between the two points is 5-0 = 5, so the slope is ...

  m = rise/run = 0/5 = 0

Then the slope-intercept equation is ...

  y = mx + b . . . . . where m is the slope and b is the y-intercept

  y = 0x +5

Simplifying, we get ...

  y = 5

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CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Murljashka [212]

Answer:

The value of DC is 66.34.

Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

The measure of ∠C is 30°.

Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

AC^{2}=AB^{2}+BC^{2}\\AC=\sqrt{AB^{2}+BC^{2}}\\=\sqrt{4^{2}+(10\sqrt{3})^{2}}\\=\sqrt{316}

Consider the right angled triangle DCA.

The angle DAC measure 75°.

Using the trigonometric identities compute the value of Perpendicular DC as follows:

tan\ 75^{o}=\frac{DC}{\sqrt{316}}\\\\DC=3.732\times\sqrt{316}\\\\DC=66.34

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3 years ago
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elixir [45]
Root: (1/4, 0)
vertical intercept: (0, -1)

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3 years ago
In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF  = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively

Read more about parallelograms at:

brainly.com/question/3050890

#SPJ1

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Answer:

B

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