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viktelen [127]
3 years ago
13

Solve this pls helpHow did the Californian gold rush have an effect on people?

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

The gold rush has a big impact on people. Especially since it helped shaped the course of California's development by bringing economic growth.

You might be interested in
Estimate each product. 2/9 of 88
kakasveta [241]
<span>19.55
</span>That's what I have gotten.
4 0
3 years ago
Your brother eats 1/6th of your birthday pizza. If the pizza has a diameter of 12 inches, what is the area that he ate
Kipish [7]

Answer:

18.84 in^2

Step-by-step explanation:

Area brother ate = 1/6 x area of pizza

a pizza is the shape of a circle. the area of a pizza is equal to the area of a circle

Area of a circle = πr²

r = 12/2 = 6

he diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

3.14 x 6^2 = 113.04

1/6 x 113.04 = 18.84

7 0
3 years ago
Which of the following is NOT true about the hypotenuse of a triangle?
fiasKO [112]

Depending on the length of the two sides of the triangle the length could be smaller than 1.

The answer that is not true is :

B. It is always greater than 1

3 0
3 years ago
Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.
nika2105 [10]

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

-x^{2} +3x+c=0

<h3>What is a quadratic equation?</h3>

Any equation of the form ax^{2} +bx+c=0 is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

D < 0

3^{2} -4(-1)(c) < 0

9+4c < 0

c < -\frac{9}{4}

For c < -\frac{9}{4} the given quadratic equation will have no real solutions.

Hence, the given quadratic equation will not have any real solution for c<-9/4.

To get more about quadratic equations visit:

brainly.com/question/1214333

5 0
2 years ago
Does anyone know how to do this ??? <br> -view attachment
cricket20 [7]

As soon as I read this, the words "law of cosines" popped
into my head.  I don't have a good intuitive feeling for the
law of cosines, but I went and looked it up (you probably
could have done that), and I found that it's exactly what
you need for this problem.

The "law of cosines" relates the lengths of the sides of any
triangle to the cosine of one of its angles ... just what we need,
since we know all the sides, and we want to find one of the angles.

To find angle-B, the law of cosines says

       b² = a² + c² - 2 a c cosine(B)

B  =  angle-B
b  =  the side opposite angle-B = 1.4
a, c = the other 2 sides = 1 and 1.9

                  (1.4)² = (1)² + (1.9)² - (2 x 1 x 1.9) cos(B)

                 1.96  =  (1) + (3.61)  -  (3.8) cos(B)

Add  3.8 cos(B)  from each side:

                 1.96 + 3.8 cos(B) = 4.61

Subtract  1.96  from each side:

                             3.8 cos(B) =  2.65

Divide each side by  3.8 :

                                  cos(B)  =  0.69737  (rounded)

Whipping out the
trusty calculator:
                                 B  = the angle whose cosine is 0.69737

                                      =  45.784° .

Now, for the first time, I'll take a deep breath, then hold it
while I look back at the question and see whether this is
anywhere near one of the choices ...

By gosh !  Choice 'B' is  45.8° !                    yay !
I'll bet that's it !

8 0
4 years ago
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