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3 years ago

Steve washed 15 cars in 3 hours.how many cars can he wash in 7 hours?

1 answer:

3 0

35 Cars because, if you times 3 by 5 it equals 15 which means that 1 hour equals 5 cars. So you times 7 by 5 and that will give you the amount of cars that were washed.

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-6.3x+14 and 1.5x-6<br> answer in simplified form

koban [17]

Answer:

The simplified form of -6.3x+14 and 1.5x-6 is -4.8x+8

Step-by-step explanation:

We have to simplify the following

-6.3x+14 and 1.5x-6

it can be written as:

=(-6.3x+14) + (1.5x-6)

Adding the like terms

=(-6.3x+1.5x)+(14-6)

= (-4.8x)+(8)

= -4.8x+8

So, the simplified form of -6.3x+14 and 1.5x-6 is -4.8x+8

3 0

3 years ago

The ratio of oil to vinegar is 8:5 how much oil blended with 7 liters vinegar for recipe

Ugo [173]

Write and solve an equation of ratios:

oil 8 x
---- = ---- = -----------
vin 5 7 liters

Then 5x = 56, and x = 56/5 liters (of vinegar)

3 0

3 years ago

dave and his sister picked out two pumpkins at the pumpkin patch. the pumpkins cost $0.47 per pound. davids pumpkin weighed 13.2

WINSTONCH [101]

Dave has 50 cents right now

4 0

3 years ago

Read 2 more answers

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

3 years ago

The complement of angle a is 20° less than half the supplement of angle a. find the measure of angle a.

igor_vitrenko [27]

Answer:

∠a=40°

Step-by-step explanation:

complement of angle a=90-a

supplement of angle a=180-a

90-a=1/2(180-a)-20

multiply by 2

180-2a=180-a-40

180-180+40=-a+2a

a=40

8 0

1 year ago