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3 years ago

9

HELPPPPPPPPPPPPPPPPPPPPPPP PLEASE HELP IMMA FAIL

1 answer:

ipn [44]3 years ago

6 0

(4+10)*6/2. If it’s the area then it’s this. Make sure you put the 4 and 10 in brackets

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Pls help and show some steps

Vikentia [17]

To solve this equation, simply plug in the value of h = 0 feet, as this would be the height the object will be on the ground. It would be 0.

Afterwards, solve the equation by factoring the quadratic function.

16t^2 - 64t - 80 = 0.
8(2t^2 - 8t - 10) = 0

2t^2 - 10t + 2t - 10 = 0

2t(t - 5) + 2(t - 5) = 0

(2t + 2)(t - 5) = 0

T = 5 and t = -1.

Since time can’t be negative, there is only one solution, t = 5.

It would be about 5 seconds.

6 0

4 years ago

What is the nonpermissible replacement of y-3/y+3

Alex787 [66]

Y = -3
-3 + 3 = 0
It is impossible to divide a number by 0

7 0

3 years ago

Which are partial products for 89 × 25?

Mrac [35]

It's C. is it klsdjifkaigfolasgfhgkajytgorfegwlhjgfso;LSHFKJsksklfds;SDH;KJSDHLF;jh;sf;LSHDF;hsjfh;;lLSDhkf'IH"LHS":LDGH:ODSHG:OLJHSGHVKHS:LGHKSdjv

4 0

4 years ago

Read 2 more answers

A surveyor wants to find the distance from points A and B to an inaccessible point C. These three points form a triangle. Becaus

harkovskaia [24]

Answer:

Part a) $AC=135.95\ m$

Part b) $BC=124.14\ m$

The diagram in the attached figure

Step-by-step explanation:

step 1

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$m\angle A+m\angle B+m\angle C=180^o$

substitute the given values

$53^o+61^o+m\angle C=180^o$

$114^o+m\angle C=180^o$

$m\angle C=180^o-114^o$

$m\angle C=66^o$

step 2

Find the distance AC

Applying the law of sines

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

see the attached figure to better understand the problem

substitute the given values

$\frac{142}{sin(66^o)}=\frac{AC}{sin(61^o)}$

$AC=\frac{142}{sin(66^o)}(sin(61^o))$

$AC=135.95\ m$ ---> rounded to the nearest hundredth

step 3

Find the distance BC

Applying the law of sines

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

substitute the given values

$\frac{142}{sin(66^o)}=\frac{BC}{sin(53^o)}$

$BC=\frac{142}{sin(66^o)}(sin(53^o))$

$BC=124.14\ m$ ---> rounded to the nearest hundredth

4 0

3 years ago

A boat traveled is 30 miles up a river in 5 hours. What was the average rate of travel, in miles per hour, of the boat

UNO [17]

6 miles per hour

30/5=6

3 0

3 years ago