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andriy [413]
3 years ago
5

Brian needs to start planning for an upcoming move. He is choosing two different size boxes to pack the majority of his stuff. T

he volume of the first is 1,728 in³ and the second is 13,824 in³. What is the ratio of the surface areas? Given that the boxes are cubes, what is the surface area of the larger of the two boxes?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Solution:

Given,

Volume of the-

First cube box=1728 in³

Second cube box=13824in³

We know that volume of cube =a³

So for the first box

a³= 1728 in³

a= 12 in

Now, surface area of the first box

6a²= 6×(12)²

= 864 in²

and for the second box

b³= 13824 in³

b= 24 in

Now, the surface area of the second box

6b²= 6×(24)²

= 3456 in²

Now, the ratio of the surface area of first box to the second box will be

864:3456

=1:4

The surface area of the larger of two boxes is

3456 in²

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Let

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<u>the answer is</u>

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The figure attached below shows the different distances involved in the problem. We heed to find the value of h, the height from Daniel's eyes. Then we'll add it to the 6 ft where his eyes are located from the ground.

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