Answer:
width of the rectangle=x=4in and length of the rectangle=11in
Step-by-step explanation:
Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.
Now, width=b=x and length=l=3x-1, thus
Perimeter of the rectangle= 2(l+b)
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Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.
Answer:
2x²+2x+8
Step-by-step explanation:
4x²-2x+10-2x²+4x-2
=4x²-2x²-2x+4x+10-2
=2x²+2x+8
The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.
Answer:
Hypotenuse MN = 10.54 ft (Approx.)
Step-by-step explanation:
Given:
Base OM = 9.6 ft
Angle θ = 13'
Find:
Hypotenuse MN
Computation:
Using trigonometry function
Cos θ = Base / Hypotenuse
Cos 13 = 9.6 / Hypotenuse
0.97 = 9.6 / Hypotenuse
Hypotenuse MN = 10.54 ft (Approx.)
