A/2-b/3=1 solve for a, add b/3 to both sides
a/2=1+b/3 which is equal to
a/2=(3+b)/3 multiply both sides by 2
a=(6+2b)/3 now you can substitute this into 2a+3b giving you:
2(6+2b)/3 + 3b which is equal to
(12+4b+9b)/3
(13b+12)/3
<span>The numbers are 4 and 7
j^2+k^2=65
4^2+7^2=65
16+49=65
65=65
hope i helped</span>
8 ... u gotta add 5+3 which is 8 soo ya\ prolly wrong (I kinda stink at math)but whatevs
Answer:
Answer Question 1:
Blank 1: Corresponding
Blank 2: congruent
Blank 3: similar
Blank 4: proportional
Question 2:
Blank 1: shape
Blank 2: size.
Step-by-step explanation:
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