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Paladinen [302]
3 years ago
5

2. Given: HM = VM, and ZH and cV Triangle congruence criteria,

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0
Answer: SAS is the correct criteria

Explanation:

Angles VMU and GMH are congruent by the Vertical Angles Theorem. Given that angles UVM and GHM are congruent because they are both right angles, we now have two pairs of corresponding angles. Also given that sides HM and VM are congruent, we now have two corresponding pairs of congruent angles and a pair of congruent sides.Therefore, your best option is the ASA postulate, which states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Therefore, we have a corresponding angle, a corresponding side, and another corresponding angle in triangle GHM, which is congruent to its corresponding angle, a corresponding side, and another corresponding angle in triangle UVM.
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Rudiy27

Answer:

x1=\frac{5+\sqrt{37}} {6}

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Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

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in this problem we have

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substitute in the formula

x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}

x=\frac{5(+/-)\sqrt{37}} {6}

x1=\frac{5+\sqrt{37}} {6}

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