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ivolga24 [154]
3 years ago
11

To raise funds for a trip, members of a high school math club are holding a game night in

Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

Answer:All positive integer less than or equal to 250

Step-by-step explanation: Teacher told me so

Veseljchak [2.6K]3 years ago
7 0

Answer:

A all numbers less than 250

Step-by-step explanation:

Not sure is fully correct tho sorry

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Help will give brainlyist
denpristay [2]

Answer:

1. 25%

2. 150%

3. 3%

4. 75%

5. 60%

6. 210%

7. 10%

8. 1%

9. 40%

10. 87.5

11. 105%

12. 2%

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find two numbers if their sum is 6.1 and their difference is 1.6
Radda [10]
For this case, the first thing we must do is define variables:
 x: unknown number (1)
 y: unknown number (2)
 We now write the equations that model the problem:
 their sum is 6.1:
 x + y = 6.1

 their difference is 1.6:
 x - y = 1.6

 Solving the system we have:
 We add both equations:
 x + x = 6.1 + 1.6

2x = 7.7

x = 7.7 / 2

x = 3.85
 Then, we look for the value of y using any of the equations:
 x - y = 1.6

y = x - 1.6

y = 3.85 - 1.6

y = 2.25
 Answer:
 
The numbers are:
 
x = 3.85

y = 2.25
6 0
3 years ago
Read 2 more answers
(5x-4) (3x+2) multiply
ivolga24 [154]

Answer:

15x^2-2x-8

Step-by-step explanation:

i did it on a paper just don't want to write cause its going to be to much to write hope this helps good luck

3 0
3 years ago
Help please. I need help with the last one
snow_lady [41]
(-1,4), (1,1), (3,-2)
6 0
3 years ago
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
2 years ago
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