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dem82 [27]
3 years ago
11

Using suitable identity find 5.62 − 0.32​

Mathematics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

5.62 - 0.32= 5.3 or 5.30

Step-by-step explanation:

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Find the indicated side of the<br> triangle.<br> b<br> 7<br> 45°<br> a<br> b = [?]VO
vodka [1.7K]

Answer:

7√2

Step-by-step explanation:

Thank to the give angle we can say that the two legs are congruent

b = \sqrt{7^2 + 7^2} = \sqrt{49+49} = \sqrt{98}

98/2 = 49

49/7 = 7

7/7 = 1

98 = 7^2 x 2

√98 = 7√2

8 0
3 years ago
Y = x^2+ 7x - 5 can be written in the form y = (x + a)^2+b
BARSIC [14]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = (x - h)² + k (h, k) are the coordinates of the vertex

Given y = x² + 7x - 5

To express in vertex form use the method of completing the square

add/subtract ( half the coefficient of the x- term )²

y = x² + 2( \frac{7}{2} )x +\frac{49}{4} - \frac{49}{4} - 5

y = (x + \frac{7}{2} )² - \frac{49}{4} - \frac{20}{4}

y = (x + \frac{7}{2} )² - \frac{69}{4}

Hence

a = \frac{7}{2} and b = - \frac{69}{4}

8 0
3 years ago
20 pts awarded and brainliest chosen<br><br>Which of the following is the solution to ?
Dvinal [7]

Answer:

B.

Step-by-step explanation:

The answer is B

5 0
3 years ago
Read 2 more answers
Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]
sveta [45]

\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle

\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}

\implies\|\vec r'(t)\|=e^t\sqrt{65}

Then

s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t

3 0
3 years ago
A certain forest covers an area of 4800 km^2 . Suppose that each year this area decreases by 5.25% . What will the area be after
9966 [12]

Answer:

the area after 6 years is  3,473 km^2

Step-by-step explanation:

The computation of the area after 6 years is as follows:

= Area × (1 - decreased percentage)^number of years

= 4,800 km^2 × (1 - 5.25%)^6

= 4,800 km^2 × 0.9475^6

= 3,473 km^2

Hence, the area after 6 years is  3,473 km^2

5 0
3 years ago
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