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adell [148]
3 years ago
8

Find the inverse of the function y = 2x^2 + 2.

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

its the last one.

Step-by-step explanation:

easy way to do inverse functions:

write out equation :

y = 2x^{2} + 2

Switch the x and y:

x = 2y^{2} + 2

Solve for y :

x = 2y^{2} + 2

subtract 2 both sides

x - 2 = 2y^{2}

Divide both sides by 2

\frac{x}{2} - \frac{2}{2} = y^{2}

reduce fraction and square root both sides

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Answer:

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Step-by-step explanation:

We can see there are 2 parts of this function: one line for x<1 (because there is a circle for x=1, meaning it disincludes it) and one line for x >= 1 (because there is a filled circle for x=1, meaning it includes it). Therefore, we can disregard choice B (because it has x <= 1 and x > 1 instead of x<1 and x>= 1).

Notice that the part that x<1 passes through the origin, meaning the y-intercept is 0. In y= mx + b form of a line, b is the y-intercept, so b = 0 and we are looking for something in the form of y = mx for x < 1. Wee see that only in choice A that this is satisfied. Therefore, the answer is A.

I hope this helps! :)

3 0
3 years ago
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So,

This is a simple subtraction problem: 7 - 2.

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Naily [24]

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4 years ago
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